Acompound is 52.14% c, 13.13% h, and 34.73% o. what is the empirical formula of the compound?

The empirical formula is .

Explanation:

If percentage are given then we are taking total mass is 100 grams.

So, the mass of each element is equal to the percentage given.

Mass of C = 52.14 g

Mass of H = 13.13 g

Mass of O = 34.73 g

Step 1 : convert given masses into moles.

Moles of C =

Moles of H =

Moles of O =

Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.

For C =

For H =

For O =

The ratio of  C: H: O = 2: 6: 1

Hence the empirical formula is .

the mass of the cathode increases because ions from the solution get reduced to atoms and become part of the cathode.

explanation:

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