Completion Use this completion exercise to check your understanding of the concepts and terms
that are introduced in this section. Each blank can be completed with a term, short
phrase, or number,
1.
2.
Solids tend to be dense and difficult to They do not
flow or take the shape of their containers, like liquids do, because
the particles in solids vibrate around 2 points. When a solid
is heated until its particles vibrate so rapidly that they are no longer
held in fixed positions, the solid
3
The
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is the
3.
4.
5.
6.
temperature at which a solid changes to a liquid. The melting and
5
7.
of a substance are at the same temperature. In general,
Pension Paceman, lek. publisargus Pearson Pombe Hal. A nights seserved
6
8.
Lonic solids tend to have relatively
melting points, while
9.
molecular solids tend to have relatively low melting points. Most
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10.
solids ane
The partides are arranged in a pattern known
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as a crystal
The smallest subunit of a crystal lattice
DISTRICT 186
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Some solids lack an ordered internal structure
... Cac
and are called
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Combustion is the act or process of burning. therefore, i believe the answer is  a: burning wood. 

Answerthis solution will not form a precipitateexplanationsolubility equilbrium:         pbf₂(s)  ⇄ pb²⁺(aq) + 2 f⁻(aq)the solubility product expression is    (we exclude solids from the equilibrium expression).now suppose we have the trial ion product q, which we can define as    then, we can interpret  q as the product of the concentration of the ions that we have and ksp as the product of the ion concentrations that are needed to form a saturated solution.if q > ksp, then that implies that there will be a surplus of ions that exceed the amount that is required to form a saturated solution. a precipitate will then form (the precipitate continually  forms until the surplus ions are removed and q is decreased to ksp's value).if q = ksp, the saturated solution that forms is barely saturated and the precipitate will be minimal.if q < ksp, then the ion concentration will not be enough to form a saturated solution (so no precipitate).using our information, we calculate the trial ion product:     since q = 2.7  × 10⁻⁸ < ksp =  4  ×  10⁻⁸, a precipitate will not form.