Grams to Grams 1N2 + 3H2 -->2NH3
If you produced 34.06g of NH3 assuming excess N2 how many grams of H2 was used?

grams H₂(g) = 6.11 grams H₂(g) used

Explanation:

Convert all given values to moles (if not already in moles), solve by rxn ratios and then convert moles to needed dimensions.

   N₂(g)   +     3H₂(g)    =>             2NH₃(g)

excess             ?                     34.6g/17g/mole = 2.04 moles

moles of H₂(g) needed = 3/2(2.04)moles = 3.05 moles H₂(g)

grams H₂(g) = 3.05 moles x 2 grams/mole = 6.11 grams H₂(g)

12 is it do you think so