In chemistry lab student is determining the salinity of seawater using a conductivity meter. The student made standards of NaCl solutions and recorded the following data: % Salinity Conductivity (ms)
0.10 1.83
0.20 3.62
0.30 5.49
0.40 7.09
0.50 8.76

The conductance of a 10 mL sample of unknown was found to be 5.82 ms.

Required:
a. Prepare a standard curve using the data above.
b. Determine the concentration of the unknown salt solution using the standard curve.

a. is an excel document. i uploaded as an attachment

b. concentration = 0.327

Explanation:

in the graph i uploaded for answer a, the x variable is conductivity,  while the y variable is % salinity.

the calculated regression line was calculated using excel =

y = 0.057655X - 0.00891

for answer part b,

we take x = 5.82

when we put this into the y formular

y = 0.057655(5.82) - 0.00891

y = 0.3355521 - 0.00891

y = 0.3266421

this is ≈ 0.327

in conclusion, using the standard curve, the concentration of unknown salt is 0.327. the % salinity = 0.327

Because electrons have negligible mass, to account for the mass of the isotope, there must be 16 neutrons, 16 neutrally charged, massive, fundamental particles present in the sulfur nucleus. and thus finally, if we have the 32s2− ion, there are 18 electrons, 16 protons, and 16 neutrons.

What are the choices?