A reaction is expected to produce 28.3 moles of hydrogen gas. If the hydrogen is collected at 297 K and 1.08 atm, what is the volume? 305 L H2 639 L H2 948 L H2 1,240 L H2

The correct answer is 639 L H₂

Explanation:

We use the ideal gas equation:

We have the following data:

n = 28.3 mol

T= 297 K

P= 1.08 atm

R= 0.082 L.atm/K.mol (gas constant)

We introduce the data in the gas equation to calculate the volume (V):

PV=nRT

⇒V =nRT/P = (28.3 mol x 0.082 L.atm/K.mol x 297 K)/(1.08 atm) = 638.2 L ≅ 639 L

Therefore, the correct option is  639 L H₂

it is the most commonly accepted one