Consider the equations below. CH,(9) →C(s)+2H2 (9) AH, = 74.6 kJ
C(s) + 2Cl2(g) → CCI (9) AH2 = -95.7 kJ
2H2(g) + 2Cl2(g) → 4HCI(9) AH2 = -184.6 kJ
CH, (g) + 4C12(g) → CCI,(9) + 4HCl(g) AH, = -205.7 kJ
Complete the following based on the diagram.
Arrow A:
Arrow B:
Arrow C:
Arrow D:

n has four pairs of electrons in the valence shell, electrons repel one another ,n has 7 protons in its nucleus, and since n has 7 protons, it must fill the second shell, giving it 4 pairs of electrons. the electrons form 3 bonds and 1 lone pair of electrons. each pair of electrons repels the other pairs, so they are equally far apart.

so all of the above