Chemistry
Chemistry, 03.03.2021 01:00, kiwipitts8661

Calculate AH® for the following: CH (8) + Ch() - CC1(0) + HC1) (unbalanced]
AH ICH (2) = -74.87 kJ/mol
AH CCl4(e)) = -96.0 kJ/mol
all ICCI(0) = -1.39 kJ/mol
AHHCUC)] = -92.31 kl/mol
AHHICK(04)) = -167.46 kJ/mol
SHICH2)) = 1210 kJ/mol

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Do you know the correct answer?
Calculate AH® for the following: CH (8) + Ch() - CC1(0) + HC1) (unbalanced]
AH ICH (2) = -74....

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