Sucrose (C12H22O11) reacts with potassium chlorate according to the following balanced equation: C12H22O11 (s) + 8 KClO3 (s) -> 12 CO2 (g) + 11 H2O (g) + 8 KCl (s)

Suppose 3.5 moles of C12H22O11 are mixed with 21.0 moles of KClO3. Identify the limiting reactant, then calculate how many moles of each product (CO2, H2O and KCl) will be formed in this reaction.

The atomic radius of sodium is 186 pm and of chlorine is 100 pm. the ionic radius for na+ is 102 pm and for cl– is 181 pm. in going from na to cl in period 3, why does the atomic radius decrease while the ionic radius increases? a. the inner electrons in the sodium cation shield its valence electrons more effectively than the inner electrons in the chloride anion do. b. the inner electrons shield the valence electrons more effectively in the chlorine atom than in the chloride anion. c. the outermost electrons in chloride experience a smaller effective nuclear charge than those in the sodium cation do. d. the outermost electrons in chloride experience a larger effective nuclear charge than those in the sodium cation do. e. monatomic ions are bigger than the atoms from which they are formed.

Can someone me with 3 and 4 plz. this is for masteries test.

What is the compound name for the formula [ru(en)2cl2]2+ and [co(en)cl2br]-