Using the equations
SrO (s) + CO₂ (g) → SrCO₃ (s) ∆H° = -234 kJ/mol
2 Sr(s) + O₂ (g) → 2 SrO (s) ∆H° = -1184 kJ/mol
CO₂ (g) → C(s) + O₂ (g) ∆H° = 394 kJ/mol
Determine the enthalpy (in kJ/mol) for the reaction
2 SrCO₃ (s) → 2 Sr (s) + 2 C(s) + 3 O₂ (g).
I also need it in exact sig figs.
Answers: 3
Chemistry, 22.06.2019 03:30, acaciacoats
The atomic radius of sodium is 186 pm and of chlorine is 100 pm. the ionic radius for na+ is 102 pm and for cl– is 181 pm. in going from na to cl in period 3, why does the atomic radius decrease while the ionic radius increases? a. the inner electrons in the sodium cation shield its valence electrons more effectively than the inner electrons in the chloride anion do. b. the inner electrons shield the valence electrons more effectively in the chlorine atom than in the chloride anion. c. the outermost electrons in chloride experience a smaller effective nuclear charge than those in the sodium cation do. d. the outermost electrons in chloride experience a larger effective nuclear charge than those in the sodium cation do. e. monatomic ions are bigger than the atoms from which they are formed.
Answers: 2
Chemistry, 22.06.2019 09:00, dante766
Achemist 16 drop copper metal from copper chloride solution. the chemist place is 0.50 g of aluminum foil in a solution containing 0.75 g of copper (ii) chloride. a single replacement reaction takes place. which statement explains the maximum amount of copper that the chemist can extract using this reaction?
Answers: 1
Using the equations
SrO (s) + CO₂ (g) → SrCO₃ (s) ∆H° = -234 kJ/mol
2 Sr(s) + O₂ (g) →...
2 Sr(s) + O₂ (g) →...
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