The value of resistance r was determined by measuring current I flowing through the resistance with an error

Correct question is;

Resistance of a given wire is obtained by measuring the current flowing in it and the voltage difference applied across it. If the percentage errors in the measurement of the current and the voltage difference are 3% each, then error in the value of resistance of the wire is?

6%

Explanation:

From ohms law, we know that;

R = V/I

Where;

R is resistance

V is voltage

I is current

Now, the percentage error in the resistance is given by the formula;

ΔR/R = ΔV/V+ ΔI/I

We are told that the current and the voltage difference have a percentage error of 3% each. Thus;

ΔR/R = 3% + 3% = 6%

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