A solution of 0.220 g of KIO3 is prepared in 50 ml volumetric flask. 2.00 mL of this solution is pipetted into a beaker with 8.00 ml distilled water, to give 10 ml of diluted KIO3. To this, 10.00 mL of starch sulfite was added. What would be the initial concentration of IO3- in this final solution

0.00044 g/mL

Explanation:

First, 0.220 g of KIO₃ are dissolved in 50 mL, so the concentration at this point is:

Then 2.00 mL of this solution are added to 8.00 mL of water (final volume = 10.00 mL). We calculate the concentration of the resulting solution:

Finally, to this 10 mL solution, another 10.00 mL were added. Thus the KIO₃ (or IO₃⁻) concentration is:

the electrical  conductivity  of asolution  of an electrolyte is measured by determining the resistance of thesolution  between two flat or cylindrical electrodes separated by a fixed distance.

its first and third is your answer i did the qustion the fourth isnt right