Calculate the number of moles of H2SO4 required to react with 0.93 moles of Al. Do not include units in your answer. Round to the tenths place or further.

1.40 moles of H₂SO₄.

Explanation:

We'll begin by writing the balanced equation for the reaction. This is illustrated below below:

2Al + 3H₂SO₄ —> Al₂(SO₄)₃ + 3H₂

From the balanced equation above,

2 moles of Al reacted with 3 moles of H₂SO₄.

Finally, we shall determine the number of mole of H₂SO₄ required to react with

0.93 moles of Al. This can be obtained as follow:

From the balanced equation above,

2 moles of Al reacted with 3 moles of H₂SO₄.

Therefore, 0.93 moles of Al will react with = (0.93 × 3)/2 = 1.40 moles of H₂SO₄.

Thus, 1.40 moles of H₂SO₄ is needed for the reaction.

when the volume of gas is   changed from   717.73 ml   to 852 ml   the temperature will   change   from 315   c to 452   c

    calculation

this is calculated using the charles law formula

that is,   v1/t1 = v2/t2

          v1=?

        t1 = 315 c   into   kelvin = 315 +273 = 588 k

        v2 = 852   ml

        t2 = 425c + 273 =698 k

make v1   the subject of the formula ( by   multiplying both side by t1)

  v1=( v2 xt1) / t2

v1= (852 ml   x 588 k)/ 698 k= 717.73 ml

the answer would be a