C3H8 (g) + 4C12 (g) → C3H4Cl4 (g) + 4HCI (g) Molar masses listed for the above equation:
C3H8 (g) = 44.1 g/mol
Cl2 (g) = 70.9 g/mol
C3H4Cl4 (g) = 181.9 g/mol
HCI (g) = 36.458 g/mol
A 4.00 mol sample of C3H8 (g) and a 6.00 mol sample of Cl2 (g) are placed in a previously
evacuated vessel, where they react according to the equation above. After one of the
reactants has been totally consumed, how many moles of HCI (g) have been produced?

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