A gas is at a pressure of 97.0 kPa and has a volume of 0.4 L If the pressure increased to 178 kPa, what will be the new volume? (Temp is constant)
Equation: P1V1 = P2V2
1.36 L
0.73 L
0.22 L
431 L

V₂ ≈ 0.22 L

General Formulas and Concepts:

Math

Pre-Algebra

Order of Operations: BPEMDAS

Brackets Parenthesis Exponents Multiplication Division Addition Subtraction Left to Right  

Equality Properties

Multiplication Property of Equality Division Property of Equality Addition Property of Equality Subtraction Property of Equality

Chemistry

Gas Laws

PressureBoyle's Law: P₁V₁ = P₂V₂Explanation:

Step 1: Define

[Given] P₁ = 97.0 kPa

[Given] V₁ = 0.4 L

[Given] P₂ = 178 kPa

[Solve] V₂

Step 2: Solve for V₂

Substitute in variables [Boyle's Law]:                                                              (97.0 kPa)(0.4 L) = (178 kPa)V₂[Boyle's Law] Multiply:                                                                                      38.8 kPa · L = (178 kPa)V₂[Boyle's Law] [Division Property of Equality] Isolate V₂ [Cancel units]:         0.217978 L = V₂[Boyle's Law] [Volume] Rewrite:                                                                      V₂ = 0.217978 L[Boyle's Law] [Volume] Round:                                                                        V₂ ≈ 0.22 L

Ithink is d. physical property

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