How many moles are in 84.23 g of ZnCl2?

84.23 grams of ZnCl2 is equal to 0.6180385366068446 moles, or for an exam friendly 0.62 moles!

0.618 moles ZnCl2

Explanation:

Divide the 84.23 g by the total grams in one mole. You can find how many grams in 1 mole (molar mass) by adding the average atomic masses of the compound. For ZnCl2 65.39+35.45+35.45 = 136.29 g/mol. Then divide that by the grams you have.

answer: the value of enthalpy change will be -152.80 kj.

solution:

pressure = 1atm , temperature = = 298 k

given that pressure and temperature are same in both gases , the number of moles of both gases can be determined by the ideal gas equation.

according to reaction 3 moles no are reacting with 1 mol of ,then 0.49 mol of no will react with moles of ozone that is 0.16 moles of ozone. since, no is limiting reagent and is an excessive reagent.

enthalpy change for the reaction between the given volumes of the gases is :

the answer is 1 i believe