Hate me, hate me, tell me how you hate me Tell me how I'm trash and you could easily replace me
Tell me that I'm strung out, wasted on the daily
Prolly 'cause there's no one around me numbin' all my pain
Prolly 'cause there's no umbrella to shield me from all the rain
Probably because you're the one playin' the mind games
You hate me because I don't let you play no mind games
They give me migraines and damage my brain
Date me, break me, easily replace me
Hopefully you see it clear, hopefully it's HD
Bet you wonder why the last few months I've been spacey
In your head, I sing
And tell me how you hate me, hate me, still tryna replace me
Chase me, chase me, tell me how you hate me
Erase me, 'rase me, wish you never dated me
Lies, tell me lies, baby, tell me how you hate me
;-;

In the following redox reaction which is the oxidizing agent and which is the reducing agent? alcl3 + na nacl + al

The grooves or folds of the brain are called

Ineed someone to see if my answers are correct! if any are wrong let me know what the correct answers would be and how to get that answer! 1. how many moles of sodium chloride are in 28 grams od nacl? a. 265 mole naclb. 856 mole naclc. 479 mole of nacld. 1.2 mole nacl < my choice2. 734 grams of lithium sulfate (li2so4) are dissolved to make 2500 ml of solution what is rhe molaratiy? a. 2.67 mb. 4.56 mc. 3.89 m < my choiced. 1.78 m3. how many grams of cacl2 would be dissolved in 3.0 l of a 0.50 m solution of cacl2? a. 250 g cacl2 b. 166.5 g cacl2c. 113.65 g cacl2d. 98 g cacl2 < my choice4. suppose you had 58.44 g of nacl and you dissolved it in exactly 2.00 liters. the molarity if the solution would be 0.5 mtrue < my choicefalse 5. i would need 22g of naoh to make a 3.0 m solution using 250 ml of solvent. true < my choicefalse6. identify the solute: you have a .0195 m solution made from using 6.5 g of solute and 3 l of solvent. identify the solute by solving for molar weight. a. the solute is nacl because the molar weight is 58.43 g/mol < my choiceb. the solute is h2so4 because the molar weight is 98.06 g/molc. the solute is cacl2 because the molar weight is 111.11 g/mol