CaCO3 → CaO + CO2 Calculate the theoretical yield of Calcium Oxide if 24.8 grams of Calcium Carbonate decomposes. Calculate the percent yield if you got 13.1 grams in the laboratory.

Theoretical yield: 13.9 g

Percent yield: 94 %

Explanation:

The reaction is:

CaCO₃ → CaO + CO₂

We see that the reaction is correctly balanced.

1 mol of calcium carbonate can decompose to 1 mol of calcium oxide and 1 mol of carbon dioxide.

We convert the mass to moles: 24.8 g . 1mol / 100.08g = 0.248 moles

As ratio is 1:1, 0.248 moles of salt can decompose to 1 mol of oxide.

We convert the moles to mass: 0.248 mol . 56.08g /1mol = 13.9 g

That's the theoretical yield.

To determine the percent yield we think:

(Determined yield / Theoretical yield) . 100 → (13.1 / 13.9) . 100 = 94 %

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