I usually don't ask for answers like this but my teacher does not offer retakes and I am so confused in chem so if anyone could help I would be so grateful. question 1: 4Al + 3O₂ → 2Al₂O₃ How many grams of Aluminum are needed if you have 1.20 moles of aluminum oxide? *
10 points
43.2 g
64.8 g
57.6 g
173 g

question 2: 4Fe + 3O₂ → 2Fe₂O₃ Given: 5.78 moles of iron, how many moles of oxygen are needed? *
10 points
4.34 mol
3.78 mol
2.84 mol
90.7 mol

question 3: N₂(g) + 3H₂(g) 2NH₃(g) There is 6.41 grams of hydrogen, how many moles of ammonia are present? *
10 points
2.27 mol
1.14 mol
2.14 mol
2.56 mol

question 4: 2P₂O₅ + 6H₂O 4H₃PO₄ Given: 4.5 grams of H₂O, how many moles of H₃PO₄ are needed? *
10 points
0.083 mol
0.75 mol
1.5 mol
0.17 mol

question 5: 2P₂O₅ + 6H₂O 4H₃PO₄ If you have 1.5 moles of H₂O, how many grams of P₂O₅ would you need? *
10 points
1917 g
213 g
71 g
98 g

question 6: F₂ + 2 NaBr → 2 NaF + Br₂ What is the correct setup of ratios to determine the mass of Bromine produced when 0.789 moles of sodium bromide are present? *
10 points
0.789 x (83/1) x (2/1)
0.789 x (1/83) x (1/2)
0.789 x (1/2) x (160/1)
0.789 x (2/1) x (160/1)

question 7: 2Al + 3Cl₂ 2AlCl₃ If you have 6.5 mol of Al, how many grams of Cl₂ are needed? *
10 points
480 g
213 g
240 g
692 g

question 8; 4Al + 3O₂ → 2Al₂O₃ Given 6.20 moles of aluminum oxide, how many grams of oxygen are needed? *
10 points
111 g
250 g
298 g
335 g

question 9: F₂ + 2 NaBr → 2 NaF + Br₂ What is the correct setup of ratios to determine the mass of sodium fluoride produced when 0.789 moles of fluorine are present? *
10 points
0.789 x (2/2) x (42/1)
0.789 x (2/1) x (1/42)
0.789 x (1/2) x (38/1)
0.789 x (2/1) x (42/1)

question 10: N₂(g) + 3H₂(g) 2NH₃(g) There is 5.41 grams NH₃, how many moles of hydrogen are needed? *
10 points
454 mol
0.477 mol
0.580 mol
16.2 mol