What is the density of aluminum chloride vapor (AlCl3) at 498 K and 0.939 atm? 1.24 g/L
3.06 g/L
5.17 g/L
7.42 g/L

B  3.06 g/L

Explanation:

formula for density is d = PM / RT

1. find given: P(pressure) = 0.939 atm, M(molar mass) = 133.33, R = 0.0821, T(temperature) = 498 K

2. plug in:  d = 0.939*133.33 / 0.0821*498 = 3.0621113 which rounds to 3.06 g/L

consider the reaction below.

 no rx

at 500 k, the reaction is at equilibrium with the following concentrations.

[pci5]= 0.0095 m

[pci3] = 0.020

[ci2] = 0.020 m

what is the equilibrium constant for the given reaction?

0.042

0.42

2.4

24

answer carbon and three oxygen atoms;