A gas has an initial volume of 15L and the pressure is at 2atm. If the temperature increases from 330K to 462K and the pressure reduced to 1 ATM, what is the new volume of the gas?

42L

Explanation:

Using the combined gas law equation as follows:

P1V1/T1 = P2V2/T2

Where;

P1 = initial pressure (atm)

P2 = final pressure (atm)

V1 = initial volume (L)

V2 = final volume (L)

T1 = initial temperature (K)

T2 = final temperature (K)

According to the provided information in this question, P1 = 2atm, V1 = 15L, T1 = 330K, T2 = 462K, P2 = 1atm, V2 = ?

Using the formula;

P1V1/T1 = P2V2/T2

2 × 15/330 = 1 × V2/462

30/330 = V2/462

Cross multiply;

462 × 30 = 330 × V2

13860 = 330V2

V2 = 13860 ÷ 330

V2 = 42L

The new volume is 42L

the seeing the electronic configuration we can say that the element is fluorine.

fluorine is the most electronegative element in the periodic table.

but by only seeing the configuration we cannot say about its reactivity because we don't know if its configuration after excitation or by addition of electrons.

but if not then, it is the lightest halogen and exists as a highly toxic pale yellow diatomic gas at standard conditions. as the most electronegative element, it is extremely reactive: almost all other elements, including some noble gases, form compounds with fluorine.