Determine the bond order in a molecule or ion with 10 valence electrons.

Bond order = 1

Explanation:

The 10 valence electrons can be added across bonding and antibonding molecular orbitals (MO) in a manner shown below:

- two 1s orbitals combine to form σ1s and σ*1s with 2 electrons in each MO

- the 3 p-orbitals combine to form σ2pz, σ*2pz with 2 electrons in each MO. In addition a degenerate π2py, π2px and π*2py, π*2px with a total of 4 electrons in each set of degenerate orbitals

Based on the energy level ordering the 10 electrons can be distributed across the bonding MO's as follows

(σ1s)²<(σ*1s)²<(σ2s)²<(σ*2s)²<(π2py)¹ = (π2px)¹

Bond order = 1/2(Bonding electrons - non-bonding electrons) = 6-4/2 = 1

answer: lol

explanation:

lol

first let us lay out the formula for potential

and kinetic energy:

pe = mgh

ke = (mv^2)/2

where: m=mass, v=velocity, g=gravitational

acceleration, h=height

calculating for mass using the known values of

pe:

340j = m (9.81 m/s^2) (50ft) (1m/3.28ft)

m = 2.27 kg

the law of conservation of energy states that

energy is neither created nor destroyed. therefore, the change in kinetic

energy from 50 ft to 35 ft would be equal to the change in potential energy

from 50 ft to 35 ft. however it would be opposite in signs since one is losing

while other is gaining.

ke(35ft) – ke(50ft) = - [ pe(35ft) – pe(50ft]

ke(50ft) = 0 since the brick is initially at rest

ke(35ft) = 340j - 2.27kg (9.81 m/s^2) (35ft)

(1m/3.28 ft)

ke(35ft)

= 102.38 j