N2+3H2=>>2NH3. If 6.72dm³ of each of Nitrogen and hydrogen (measured at S. T.P.) are made to produced Ammonium. Which of the reacted will be in excess and by how many moles?

Hydrogen, 0,2 mol

Explanation:

= 22, 4 l/mol

V () = 6,72 = 6,72 l

V () = 6,72 = 6,72 l

The formula is:

n =

n  () = 6,72l /22,4 l/mol = 0,3 mol

n  () = 6,72l /22,4 l/mol = 0,3 mol (the same)

But from the equation we get a proportion that 1 mol  () - 3 mol ()

(we have more hydrogen than is need for the reaction)

So there is excess of

We only need   = 0,1 mol ()

0,3 mol (hydrogen quantity we have) - 0,1 mol (hydrogen quantity we need for the reaction) = 0,2 mol (excess)

make me the brainliest

because u need two or more forms of the same element that contain equal numbers of protons but different numbers of neutrons in their nuclei to form isotopes.

so since they all have the same shape? i mean maybe because m& m and reeses are both chocolates

with this one i know the answer in craters one reason i looked it up and i learned about it there is my evidence