How many atoms of K are present in 195.49 grams of K? O 3.0110 x 1024

O 6.0220 x 1024

O 1.1772 x 1026

0 4.5797 x 1027

3.011*10²⁴ atoms of K are present in 195.49 grams of K

Explanation:

Since the molar mass of potassium K is 39.1 g/mole, then you can apply the following rule of three: if 39.1 grams are contained in 1 mole, 195.49 grams will be contained in how many moles?

amount of moles≅ 5 moles

Avogadro's Number or Avogadro's Constant is the number of particles that make up a substance (usually atoms or molecules) and that can be found in the amount of one mole of said substance. Its value is 6.023*10²³ particles per mole.

You can apply the following rule of three: if by definition of Avogadro's Number 1 mole contains 6.023*10²³ atoms, 5 moles will contain how many atoms?

amount of atoms= 3.011*10²⁴

3.011*10²⁴ atoms of K are present in 195.49 grams of K

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