If 175 g of phosphoric acid reacts with 150.0 g of sodium hydroxide, what is the limiting reactant? How many grams of sodium phosphate will produced? How many grams of excess reactant will be left over?

NaOH is the limiting reactant.

204.9 g of sodium phosphate are formed.

51.94 g of excess reactant will remain.

Explanation:

The reaction that takes place is:

First we convert the mass of both reactants to moles, using their respective molar masses:

1.78 moles of H₃PO₄ would react completely with (1.78 * 3) 5.34 moles of NaOH. There are not as many NaOH moles so NaOH is the limiting reactant.

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We calculate the produced moles of Na₃PO₄ using the limiting reactant:

Then we convert moles into grams:

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We calculate how many H₃PO₄ moles would react with 3.75 NaOH moles:

We substract that amount from the original amount:

Finally we convert those remaining moles to grams:

oxygen, selenium, tellurium, and polonium.

they're all from the same group as sulfur (group 16).