1. A 7.546 g sample of an unknown compound was analyzed and found to contain only nitrogen and oxygen. If the mass of nitrogen present in the sample was 1.957 g, determine the empirical formula
of the compound

N₂O₅

Explanation:

From the question given above, the following data were obtained:

Mass of compound = 7.546 g

Mass of nitrogen (N) = 1.957 g

Empirical formula =?

Next, we shall determine the mass of oxygen present in the compound. This can be obtained as follow:

Mass of compound = 7.546 g

Mass of nitrogen (N) = 1.957 g

Mass of Oxygen (O) =?

Mass of O = (Mass of compound) – (Mass of N)

Mass of O = 7.546 – 1.957

Mass of O = 5.589 g

Finally, we shall determine the empirical formula of the compound. This can be obtained as follow:

Mass of nitrogen (N) = 1.957 g

Mass of oxygen (O) = 5.589 g

Divide by their molar mass

N = 1.957 / 14 = 0.14

O = 5.589 / 16 = 0.35

Divide by the smallest

N = 0.140 / 0.14 = 1

O = 0.35 / 0.14 = 2.5

Multiply through by 2 to express in whole number

N = 1 × 2 = 2

O = 2.5 × 2 = 5

The empirical formula of the compound is N₂O₅.

when atmosphere interacts with biosphere they focuses on on the sources and sinks of green house gases (ghgs) air pollutants, particular matters, water and energy between the earth's surface and the atmosphere. the biosphere affects the climate. the atmosphere and biosphere are in constant interaction with each other, and all living things rely on gases in the atmosphere for life. organisms such as animals take in oxygen gas form the atmosphere to use in every cell of their body for smooth functioning of daily routine exercises.

hydrocarbons are organic compounds that contain only hydrogens and carbons. they can be saturated (those which contain only carbon-carbon single bonds) or unsaturated (those which contain carbon-carbon double or triple bonds) in nature. hydrocarbons can undergo several reactions like substitution, elimination etc.  

on substituting one or more hydrogen atoms in hydrocarbon it results in the formation of haloalkane. as the halogen atoms are large compared to the carbon and hydrogen atoms, due to which the molecular weight increases and the bond become polar because of presence electronegative halogen atom and results in the increase in boiling point of the haloalkane.

thus, the correct option is (b) that is the boiling point of the new compound increases on substituting a hydrogen atom with a halogen in a hydrocarbon.