1.7 mol Zn and 6.7 mol HCl react according to the equation
Zn + 2HCI - ZnCl2 + H2.
If the limiting reactant is Zn, calculate the
amount of ZnCl2 formed.
Answer in units of mol.

(part 2 of 2)
Calculate the amount of H2 formed.
Answer in units of mol.

This is a two part question.. If you can explain the steps it would be greatly appreciated also!!

when the volume of gas is   changed from   717.73 ml   to 852 ml   the temperature will   change   from 315   c to 452   c

    calculation

this is calculated using the charles law formula

that is,   v1/t1 = v2/t2

          v1=?

        t1 = 315 c   into   kelvin = 315 +273 = 588 k

        v2 = 852   ml

        t2 = 425c + 273 =698 k

make v1   the subject of the formula ( by   multiplying both side by t1)

  v1=( v2 xt1) / t2

v1= (852 ml   x 588 k)/ 698 k= 717.73 ml

c-14 is carbon-14, or radiocarbon.   it is a radioactive isotope of carbon with an atomic nucleus containing 6 protons and 8 neutrons.

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