Draw the Zaitsev product formed when 2,3‑dimethylpentan‑3‑ol undergoes an E1 dehydration. The starting material is a chiral carbon with an in plane bond pointing up to methyl and an in plane bond to O H pointing to the lower right. There is a wedged bond to isopropyl pointing to the lower left and a dashed bond to ethyl pointing to the left. This reacts with H 3 P O 4 in an E 1 reaction to give the Zaitsev product.

See explanation

Explanation:

Dehydration of an alcohol by E1 mechanism occurs in two steps. The first step is the is the protonation of the -OH group in the alcohol followed by the elimination of water, a good leaving group.

In the case of  2,3‑dimethylpentan‑3‑ol, the carbocation formed undergoes rearrangement followed by loss of a hydrogen atom. This now yields the product as shown in the image attached.

Note that, the Zaitsev's product is the most substituted product and is most stable hence it is the most favored product.

calculate how many grams of ammonia can be produced from 4.21 grams of

n2 + 3h2 = 2nh3

my answer:

25.0g n2 x (1 mol/ 28.0gn2) x (2 mol nh3/ 1 mol n2) x (17.0g nh3/ 1 molnh3) = 30.36g n2

25.0g h2 x (1 mol h2/ 2.00g h2) x (2 mol nh3/ 3 mol h2) x (17.0g nh3/ 1 mol nh3) = 141.67g h2

lr = n2