Suppose you weigh the unknown substance on an electronic balance and find it has a mass of 445 grams. Analyzing the products of decomposition, you find that the masses of the elements in the sample are 232 grams of carbon, 58 grams of hydrogen, and 155 grams of oxygen. Finally, through further experimentation, you determine that the molar mass of the compound is 46.07 grams/mole. Calculate the amount, in moles, of each component element in your substance. Use the periodic table to help you find the necessary molar masses.

moles of carbon

moles of hydrogen

moles of oxygen

19.32 = moles of carbon

57.54 = moles of hydrogen

9.69 = moles of oxygen

Explanation:

232 g carbon × 1 mol C / 12.011 g C= 19.32 mol C

58 g hydrogen × 1 mol H / 1.008 g H = 57.54 mol H

155 g oxygen × 1 mol O / 15.999 g O = 9.69 mol O

when the volume of gas is   changed from   717.73 ml   to 852 ml   the temperature will   change   from 315   c to 452   c

    calculation

this is calculated using the charles law formula

that is,   v1/t1 = v2/t2

          v1=?

        t1 = 315 c   into   kelvin = 315 +273 = 588 k

        v2 = 852   ml

        t2 = 425c + 273 =698 k

make v1   the subject of the formula ( by   multiplying both side by t1)

  v1=( v2 xt1) / t2

v1= (852 ml   x 588 k)/ 698 k= 717.73 ml

warm front forms when a moist, warm air mass slides up and over a cold air mass. as the warm air mass rises, it condenses into a broad area of clouds. a warm front brings gentle rain or light snow, followed by warmer, milder weather.

hope i !