If 0.332 mol of zinc reacts with excess lead(IV) sulfate, how many grams of zinc sulfate will be produced in the reaction?

53.6 g

Explanation:

Step 1: Write the balanced equation

2 Zn + Pb(SO₄)₂ ⇒ 2 ZnSO₄ + Pb

Step 2: Calculate the moles of ZnSO₄ produced from 0.332 moles of Zn

The molar ratio of Zn to ZnSO₄ is 2:2. The moles of ZnSO₄ produced are 2/2 × 0.0332 mol = 0.0332 mol.

Step 3: Calculate the mass corresponding to 0.332 moles of ZnSO₄

The molar mass of ZnSO₄ is 161.44 g/mol.

0.332 mol × 161.44 g/mol = 53.6 g

alkaline metals are lithium, sodium, rubidium, potassium, cesium and francium.

alkali metals have electronegativity from 0.7 to 1, lowest in periodic table of elements, which means that alkali metals (i group in periodic table) has positive oxidation number in compounds.

electronegativity is a chemical property that describes the tendency of an atom to attract a shared pair of electrons towards itself.

alkaline metals (far left in main group) have lowest ionizations energy and easy remove valence electrons,

for example, potassium is the alkali metal and has a single valence electron in the outer electron shell.

electron configuration of potassium is: ₁₉k 1s²2s²2p⁶3s²3p⁶4s¹.

they can not exist alone in nature, because they are very reactive.