What volume (in L) of water vapor will be produced from the reaction of 24.65 L of oxygen?

2C2H6(g) + 702(g) —4CO2(g) + 6H2O(9)

21.13 L of will be produced from the reaction of 24.65 L of oxygen

Explanation:

According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP and contains avogadro's number of particles.

According to stoichiometry :

7 moles of give = 6 moles of vapour  

 of produce = of vapour  

Thus 24.65 L of produce = L of vapour  

21.13 L of will be produced from the reaction of 24.65 L of oxygen

1. for the first question, we must find the mass of the anhydrous salt, mgso₄. the molar mass for mgso₄·7h₂o is 246.47 g/mol, while that of mgso₄ is 120.37 g/mol.7.834 g mgso₄·7h₂o * 1 mol mgso₄·7h₂o/246.47 g * 1 mol mgso₄/1 mol mgso₄·7h₂o * 20.37 g mgso₄/mol = 0.647 g mgso₄

2. mass of water = mass of sample - mass of anhydrous salemass of water = 7.834 - 0.647 = 7.19 gpercent water in hydrate = 7.19/7.834 * 100 = 91.74%