Chemistry
Chemistry, 08.02.2021 18:10, josephv80

The emf of the cell: Ni/Ni^+2 (1.0 M) // Au^+3 (1.0 M)/ Au (E°= -0.25 V for Ni^+2/Ni; E°= 1.5 V for Au^+3/Au) is =
A) 1.25v
B) -1.25v
C) 1.75v
D) 2.0v
please help me

answer
Answers: 3

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The emf of the cell: Ni/Ni^+2 (1.0 M) // Au^+3 (1.0 M)/ Au (E°= -0.25 V for Ni^+2/Ni; E°= 1.5 V for...

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