How many grams of O2 are formed from 13.34 moles of KClO3? Provide your final answer rounded to two decimal places. 2 KClO3 → 2 KCl + 3 O2

640.32 g

Explanation:

2KClO₃ → 2KCl + 3O₂

First we convert KClO₃ moles to O₂ moles, using the stoichiometric coefficients:

Then we convert O₂ moles to grams, using its molar mass:

So 640.32 g of O₂ are formed from 13.34 moles of KClO₃.

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