The following reaction shows the products when sulfuric acid and aluminum hydroxide react. 2Al(OH)3 + 3H2SO4 → Al2(SO4)3 + 6H2O The table shows the calculated amounts of reactants and products when the reaction was conducted in a laboratory. Initial Mass and Yield Sulfuric Acid Aluminum Hydroxide Initial Amount of Reactant 40 g 45 g Theoretical Yield of Water from Reactant 14.69 g 31.15 g What is the approximate amount of the leftover reactant? 20.89 g of sulfuric acid 22.44 g of sulfuric acid 21.22 g of aluminum hydroxide 23.78 g of aluminum hydroxide

2fe + 3h2so4 -> fe2(so4)3 + 3h2

it is necessary to balance equations in order to get the proper amount of reactants as well as products in order not to make a miscalculation.

you cannot change the subscripts as that would change the substance itself. for instance, diatomic elements such as h2 only have the subscript two when a gas. another example would be so4, if you were to change the subscript, the element would no longer be sulfate.

we change the coefficients instead as that only changes the number of molecules rather than the substance itself.

hope this !

um i think it might be a car?