Use coulomb\'s law to calculate the energy of a magnesium ion and an oxide ion at their equilibrium ion-pair separation distance.

The energy required to separate the ion pair = 4.297×10^(−19)J .

We know that

F = k * q1 * q2 / d^2

Force of attraction F

K = 8.99 x 10^9

q1 = charge on Mg = +2  = 2 X 1.9 x 10^-19 C

q2 = charge on O = -2 = 2 X 1.9 x 10^-19 C

d = distance between two ions = 72 + 140 pm = 212 pm

Force = 8.99 x 10^9 X 2 X 1.9 x 10^-19 C X 2 X 1.9 x 10^-19 C / (212 X 10^-12 )^2

Force = 0.002889 X 10^-5 = 2.889 X 10^-8 N

each  column  of the  table  is called a group. elements in a group share similar properties. groups are  read  from  top  to  bottom. metal. metalloid. nonmetal. solid. liquid. gas. fe. hg. o.  2. 3. 4. 5. 6. 7. 8. 9.  2. beryllium. 9.012. 4.  sodium. 22.990.  11. 3.  magnesium. 24.305.  12.  potassium. 39.098.  19. 4.  calcium. 40.078.  20. i guess  i