38. For a chemical reaction of the type AB
K=2.0 and BC K=0.01
Equilibrium constant for the reaction 2C 2 A is:
A. 25
B. 50 C. 2500 D.4 x 10-

Equilibrium constant for the reaction 2C ⇔2 A is : 2500

Given

A⇔B, k = 2.0

B⇔C, k = 0.01

Required

k for 2C⇔2A

Solution

k₁ for A⇔B :(eq 1)

k₂ for B ⇔C :(eq 2)

k for 2C⇔2A :

k₁ x k₂ =

Reverse :

with this one i know the answer in craters one reason i looked it up and i learned about it there is my evidence

as given the equation is

2al + 6 hcl > 2 alcl3 + 3 h2(g)

as per equation two moles of aluminum reacts with six moles of hcl to give two moles of alcl3 and three moles of hydrogen gas

given: three moles of al are present and 7 moles of hcl

for three moles of aluminum nine moles of hcl will be required

however as 7 moles of hcl are present so the limiting reagent is hcl

hcl is going to decide the number of moles of product formed

when six moles of hcl are present = 3 moles of h2 are formed

when one mole of hcl is present == 3/6 mole sof h2 will be formed

when 7 moles of hcl are present = 3 x 7/ 6 moles of h2 will be formed = 3.5 moles of h2