If 4.5 moles of AlCl3 were made, how many moles of CuCl2 were used?

6.75 moles of CuCl₂ were used

Explanation:

Given data:

Number of moles of AlCl₃ formed = 4.5 mol

Number of moles of CuCl₂ used = ?

Solution:

Chemical equation:

3CuCl₂ + 2Al  →   2AlCl₃ + 3Cu

Now we will compare the moles of CuCl₂ and AlCl₃

               AlCl₃       :      CuCl₂

                   2         :        3

                 4.5        :      3/2×4.5 = 6.75

6.75 moles of CuCl₂ were used.

when [oh-] is 10-5  m, and [h3o+] is 10-9  m, the poh is 5 and ph is 9. again in both cases the sum of ph and poh is 14. however, the hydrogen ion concentration is not always going to be equal to exactly 1 x 10 raised to a negative number. for example, we skipped over the value of 2.0 x 10-7.