Given the following equation: CH4 + 202 CO2 + 2H2O How many grams of CH4 are needed to react with 3.2 grams of O2?

Mass = 0.8 g

Explanation:

Given data:

Mass of oxygen = 3.2 g

Mass of CH₄ = ?

Solution:

Chemical equation:

CH₄ + 2O₂     →     CO₂ + 2H₂O

Number of moles of O₂:

Number of moles = mass/molar mass

Number of moles = 3.2 g/ 32 g/mol

Number of moles = 0.1 mol

Now we will compare the moles of CH₄ and O₂.

                         O₂          :       CH₄  

                           2          :          1

                         0.1         :        1/2 = 0.1 = 0.05

Mass of CH₄:

Mass = number of moles × molar mass

Mass = 0.05 mol ×  16 g/mol

Mass = 0.8 g

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