Given 26,1 grams of aluminum (AI) and excess oxygen (Os), how many grams of aluminium oxide (AL) can be produced?

2Al+

2

3

O

2

⟶Al

2

O

3

Moles of Al=

27

27

=1 mol

2 mole Al gives

2

3

mole O

2

1 mole Al gives

4

3

mole O

2

Mass of oxygen =

4

3

×32=24 gram

Hence, the correct option ios (A)

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