115 mL of a 2.35 M potassium fluoride (KF) solution is diluted with 1.28 L of water. What is the new concentration in molarity?
? M KF

The new concentration : = 0.194 M

Given

115 mL(0.115 L) of a 2.35 M Potassium  fluoride (KF)

1.28 L of water

Required

The new concentration

Solution

Dilution is the process of adding solvent to get a more dilute solution.

The moles(n) before and after dilution are the same.

Can be formulated :

M₁V₁=M₂V₂  

M₁ = Molarity of the solution before dilution  

V₁ = volume of the solution before dilution  

M₂ = Molarity of the solution after dilution  

V₂ = volume of the solution after dilution

V₂=0.115 + 1.28 = 1.395 L

Input the value :

M₂ = (M₁V₁)/V₂

M₂ = (2.35 x 0.115)/1.395

M₂ = 0.194

the answer to this question is 3.