A force of 7 N acts on an object. The displacement is, say 8 m, in the direction of the force. Let us take it that the force acts on the object through the displacement. What is the work done in this case?

56 J

Explanation:

Step 1: Given data

Step 2: Calculate the work (w) done on the object

We can find the work done on the object using the following expression.

w = F × d × cosθ

where

θ is the angle between F and d

Since F and d occur in the same direction, θ = 0° and cosθ = 1. Then,

w = F × d × 1

w = F × d

w = 7 N × 8 m = 56 J

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specific gravity is the density of a substance divided by the density of water. since (at standard temperature and pressure) water has a density of 1 gram/cm3, and since all of the units cancel, specific gravity is usually very close to the same value as density

so "c" is the answer

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