How many grams of sugar are in 50 mL sample of a 2.4 sucrose solution?

Mass of sucrose : = 41.076 g

Given

50 ml sample of a  2.4 M sucrose solution(C₁₂H₂₂O₁₁)

Required

Mass of sugar

Solution

Mol sucrose :

= M(molarity) x V(volume)

= 2.4 x 50

= 120 mlmol

= 0.12 mol

Mass of sugar :

= mol x MW

= 0.12 x 342,3 g/mol

= 41.076 g

answer: the value of enthalpy change will be -152.80 kj.

solution:

pressure = 1atm , temperature = = 298 k

given that pressure and temperature are same in both gases , the number of moles of both gases can be determined by the ideal gas equation.

according to reaction 3 moles no are reacting with 1 mol of ,then 0.49 mol of no will react with moles of ozone that is 0.16 moles of ozone. since, no is limiting reagent and is an excessive reagent.

enthalpy change for the reaction between the given volumes of the gases is :

2b2t

explanation:

2b2t