A student increases the temperature of a 673 cm^3 balloon from 275 K to 460 K. Assuming constant pressure, what should the new volume of the balloon be?

Round your answer to one decimal place.

1125.75 cm³

Explanation:

We are given;

Initial volume; V1 = 673 cm³

Initial temperature; T1 = 275 K

Final temperature; T2 = 460 K

From Charles law, we can find the new volume from;

V1/T1 = V2/T2

V2 = (V1 × T2)/T1

V2 = (673 × 460)/275

V2 = 1125.75 cm³

a pan containing water is placed in a positio n where it is exposed to a 10 mile per hour wind. the pan contains a uniform depth of 1.27 cm of water, is quite wide, and has a length of 2.44 m in the wind direction. the water in the pan is at a constant temperature of 15.5 °c.