1) if I have a 30 mole sample of gas at a temperature of 120˚C, and a volume of 300 L. What is the pressure of the gas on the container?

P = 3.23 atm

Explanation:

Given data:

Number of moles of gas = 30 mol

Temperature = 120°C

Volume of gas = 300 L

Pressure of gas = ?

Solution:

PV = nRT

P= Pressure

V = volume

n = number of moles

R = general gas constant = 0.0821 atm.L/ mol.K  

T = temperature in kelvin

Now we will convert the temperature.

120+273.15 = 393.15 K

P × 300 L = 30 mol × 0.0821 atm.L/mol.K × 393.15 K

P = 968.33 atm. L /300 L

P = 3.23 atm

the volume of fluid displaced would equal the volume of the gas. use a gas syringe - this is a laboratory instrument that can be used to withdraw a certain volume of gas from a closed system or to measure the volume of gas from a chemical reaction.

it is to be noted that an alpha particle is an helium nucleus. so it contains 2 protons 2 neutrons and has a mass number of 4. when alpha decay particles are ejected from the nucleus it gets transformed into an atom which has atomic number less than 2 and a mass number less than 4.

an equation that could represent alpha decay is radium 226 decay of alpha particle forms radon 222.

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