How many grams is 4.15 liters of O2 at stp?

Mass = 5.92 g

Explanation:

Given data:

Volume of O₂ = 4.15 mol

Temperature and pressure = standard

Mass in gram = ?

Solution:

The given problem will be solve by using general gas equation,

PV = nRT

P= Pressure

V = volume

n = number of moles

R = general gas constant = 0.0821 atm.L/ mol.K  

T = temperature in kelvin

By putting values,

1 atm × 4.15L = n ×0.0821 atm.L /mol.K × 273.15 k

4.15 atm.L = n ×22.43 atm.L /mol

n = 4.15 atm.L / 22.43 atm.L /mol

n = 0.185 mol

Mass in gram:

Mas = number of moles × molar mass

Mass = 0.185 mol ×32g/mol

Mass = 5.92 g

in scientific notation, the value of the  speed of light in a vacuum

  will be written as 2.995 * 10^8. when this value is represented in the form of

  a * 10^b, then, a = 2.995 and b = 8.

the value of the speed of light in a vacuum given above can also be rounded up to approximately 300000000. in this case, the scientific notation will be written as 3 *10^8.