How many oxygen atoms are in 10.0g of 2Al2 CO3 3

0.776 ×10²³ atoms of oxygen

Explanation:

Given data:

Mass of Al₂CO₃ = 10.0 g

Number of atoms of oxygen = ?

Solution:

Number of moles of Al₂CO₃:

Number of moles = mass/molar mass

Number of moles = 10.0 g/233.99 g/mol

Number of moles = 0.043 mol

1 mole of Al₂CO₃ contain 3 mole of oxygen.

0.043 ×3 mol = 0.129 mol

Number of atoms of oxygen:

1 mole contain 6.022×10²³ atoms

0.129 mol × 6.022×10²³ atoms / 1mol

0.776 ×10²³ atoms of oxygen

i think that the answer is c

substituting a hydrogen atom with a halogen in a hydrocarbon:

- the single bond remains single. a is wrong.

- the bond with hydrogen is as strong as with a halogen. c is wrong

- a hydrocarbon is saturated if there is no double bond. we do not know that so d is wrong.

- carbon will always have four valence electrons. e is wrong.

by elimination, the correct answer is b. the boiling point of the new compound increases.