Arnold kept a water log as a project for his chemistry class. Arnold's family consists of Arnold, his sister, and his parents for a total family size of four. He measured each family member's water usage every day for a week, and found that the family used an average of 457 gal/day. Arnold's city charges $0.223/cgal of water. The unit centigallon (cgal) is used by cities to measure the volume of water used, where 1 cgal is equal to 100 gal. Assuming this average usage continues, how much does Arnold expect his family to pay in a year for water usage?

$ 1487.90 .

Explanation:

Family size = 4

Water usage per member = 457 gal / day .

Water usage for whole family = 457 x 4

Use of water in one year for family = 457 x 365 x 4 = 667220 gal

667220 gal = 667220 / 100 = 6672.20 cgal .

expense per cgal = $ 0.223

Total yearly expected expense = 0.223 x 6672.20

= $ 1487.90

the density of gold = 19.3 g/cm3

the relation between density and mass and volume is

density = mass / volume

given :

mass of gold = 13 g

density = 13g / volume = 19.3

volume = 13 /19.3 = 0.67 cm^3

thus volume of gold nugget = 0.67 cm^3

air

in a tire you fill a tire with air

then a couple days later you check the air pressure in the tire

hope this mark me brainliest