What is the mass of 2.53x10^34 atoms of Ni?

2.48 g

Explanation:

From the question given above, the following data were obtained:

Number of atoms = 2.53×10³⁴ atoms

Mass of Ni =?

From Avogadro's hypothesis,

we understood that 1 mole of any substance contains 6.02×10²³ atoms.

Therefore, 1 mole of Ni contains 6.02×10²³ atoms.

Recall:

1 mole Ni = 59 g

Therefore, 59 g of Ni contains 6.02×10²³ atoms.

Finally, we shall determine the mass of 2.53×10³⁴ atoms of Ni. This can be obtained as follow:

6.02×10²³ atoms = 59 g

Therefore,

2.53×10³⁴ = 2.53×10³⁴ × 59 / 6.02×10²³

2.53×10³⁴ atoms = 2.48 g

Thus, the mass of 2.53×10³⁴ atoms of Ni is 2.48 g.

in chemistry, adhesion and cohesion are attractive forces that exist between molecules. they hold the molecules together from each other. they are different in that adhesive force exists between molecules of different substance while cohesive force happens between molecules of same substance.

adhesion between water and glass causes water molecules at the edge of water and glass interface to climb up the wall in a narrow glass tube. this is called capillary action. cohesion is what gives glass its shape and causes water to form a droplet.