What is the percent by volume of HCl in a solution prepared by mixing 60.0 mL HCl with 0.800 L H2O? answere: 6.98%
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The percent by volume of HCl in the solution is approximately 6.98%

Explanation:

The given parameters are;

The volume of HCl solute added to make the mixture = 60.0 mL = 0.06 L

The volume of H₂O solvent to which the HCl is added to make the mixture = 0.800 L

The volume of the mixture (solution) formed by mixing the HCl and H₂O = 0.06 L + 0.800 L = 0.860 L

The percentage by volume, (% V/V) of a component in a mixture is given as follows;

Substituting the known and derived values from above, we have;

∴ The percent by volume of HCl in the solution is  %V/V HCl ≈ 6.98%.

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