Part b (r)–3-chloro-2-methylhexane will undergo a nucleophilic substitution reaction in the presence of sodium ethoxide and ethanol. complete the mechanism for the sn2 reaction and draw the products of the reaction. draw all missing reactants and/or products in the appropriate boxes by placing atoms on the grid and connecting them with bonds and including charges where needed. indicate the mechanism by drawing the electron-flow arrows on the molecules. arrows should start on an atom or a bond and should end on an atom, bond, or where a new bond should be created.

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Explanation:

To understand this, we need to make the reaction involved with the given configuration. Configuration R means that the substituents of the molecule, the priority order goes clockwise (From heaviest to lightest) so, if an Sn2 is ocurring in the reaction this means that the nucleophile, which in this case, is the sodium ethoxide will attack the molecule in the opposite side of the leaving group (which is the chlorine).

Also when this occurs, as Sn2 is a bimolecular reaction and is held in one step, it occurs an inversion in the configuration of the product. So, it's the innitial reactant was R, then the final product will be S.

The mechanism and product can be watched in the attached picture

Hope this helps.

in 1783 cavendish was working with his hydrogen gas and found that when he burned it and condensed the vapor it was water. this was very significant since it disproved the greek theory of elements completely since water was not a simple substance but the product of two gases. it was lavoisier who hearing of the experiment gave cavendish's gas the name hydrogen ("water-producer") and added that hydrogen burned by combining with oxygen and that water was a hydrogen-oxygen combination.

explanation: