In his experiment, Balmer introduced hydrogen gas in a discharged tube in order to excite electrons on higher energy levels. Then, as the electrons dropped down to lower energy levels, photons were emitted by the atoms. What is the energy of a photon emitted by a electron dropping from level n

2.56 eV

Explanation:

Using the formula;

ΔE= -RH(1/n^2final - 1/n^2initial)

RH = -2.18 * 10-18 J

nfinal = 2

ninitial =1

Substituting values;

ΔE= -2.18 * 10-18 J(1/4^2 - 1/2^2)

ΔE= -2.18 * 10-18 J(0.0625 - 0.25)

ΔE= 4.09 * 10^-19 J

To convert to eV

4.09 * 10^-19 J/1.6 * 10^-19

=2.56 eV

answer: the rate of diffusion increases with increase in temperature.

increase in temperature, increases the molecular/particles speed (kinetic energy. diffusion means movement of particles through the material.

generally, the heavier the particle the more it interacts with the environment and more the temperature matters. so higher temperature results in higher diffusion.

how to make a simple air condition